Question

2) Dadas as retas paralelas cortadas por uma transversal a seguir, calcule a + b. 3x + 18 5x - 10 a b​

Answer 1

Resposta:

calcule a + b. 3x + 18, 5x - 10.

A=5x-10 (Solving the calculation by the letter a, the result will be the same as in the question).

Let's solve for x.

a=5x−10

Step 1: Flip the equation.

5x−10=a

Step 2: Add 10 to both sides.

5x−10+10=a+10

5x=a+10

Step 3: Divide both sides by 5.

5x/5=a+10/5

x=⅕ a+2

B=3x+18 (Solving the calculation by the letter b, the result will be the same as in the question).

Let's solve for x.

b=3x+18

Step 1: Flip the equation.

3x+18=b

Step 2: Add -18 to both sides.

3x+18+−18=b+−18

3x=b−18

Step 3: Divide both sides by 3.

3x/3=b−18/3

x=⅓ b−6

Explicação passo a passo: