Question

2) Dada a função quadrática f(x) = 3x² - 4x + 1, determina: a) f(1) b) f( 2 ) c) f(- 1) d) f(0) e) f(-2)

Answer 1

Oie, Td Bom?!

• Seja a função:

$f(x) = 3x {}^{2} - 4x + 1$

a)

$f(1) = 3 \: . \: 1 {}^{2} - 4 \: . \: 1 + 1$

$f(1) = 3 \: . \: 1 - 4 + 1$

$f(1) = 3 - 4 + 1$

$f(1) = 4 - 4$

$f(1) = 0$

b)

$f(2) = 3 \: . \: 2 {}^{2} - 4 \: . \: 2 + 1$

$f(2) = 3 \: . \: 4 - 8 + 1$

$f(2) = 12 - 8 + 1$

$f(2) = 13 - 8$

$f(2) = 5$

c)

$f( - 1) = 3 \: . \: ( - 1) {}^{2} - 4 \: . \: ( - 1) + 1$

$f( - 1) = 3 \: . \: 1 +4 + 1$

$f( - 1) = 3 + 4 + 1$

$f( - 1) = 7 + 1$

$f( - 1) = 8$

d)

$f(0) = 3 \: . \: 0 {}^{2} - 4 \: . \: 0 + 1$

$f(0) = 3 \: . \: 0 - 0 + 1$

$f(0 )= 0 + 1$

$f(0) = 1$

e)

$f( - 2) = 3 \: . \: ( - 2) {}^{2} - 4 \: . \: ( - 2) + 1$

$f( - 2) = 3 \: . \: 4 + 8 + 1$

$f( - 2) = 12 + 8 + 1$

$f( - 2) = 20 + 1$

$f( - 2) = 21$

Att. Makaveli1996