Question

2.Considerando log 2 = 0,3010 e log 3 = 0,4771, calcule:

a) log6 4 = 0,773

b) log9 12

c)log4 100

d) log8 9

e) log3 10

Answer 1

Resposta:a) log8=log2^3

2log3=2.0,3010=0,6020

b)log12=log2.2.3=log2+log2+log3

                      0,3010+0,3010+0,4771=1,0791

c) log72=log2^3.3^2

log2^3+log3^2=3log2+2log3

3.0,3010+2.0,4771

0,903+0.9542

1,8572

d)log√2

log2^1/2

1/2log2

0,3010/2=0,1505

e) log√108

log2^2.3^3

log2^2+log3^3

2.log2+3log3

2.0,3010+3.0,4771

0,602+1,4313=2,0333

e)log5

log10/2

log10-log2

1-0,3010=0,699