Question

      2) Coloque, nas seguintes proporções, os termos que faltam:  
a) 5/7=?/35
b) 6/11 = 24/?
c) ?/4=18/24
d) 9/?=45/65
e) 6/18=?/54
f) 1/2=3/?
g) 6/?=9/12
h) 3/?=12/60

me ajudem por favor e urgente??​

Answer 1

$\large\boxed{\begin{array}{l}\sf\dfrac{a}{b}=\dfrac{c}{d}\implies a\cdot d=b\cdot c\\\rm'' O~produto~dos~extremos~\acute e~igual~ao~produto\\\rm dos~meios''\end{array}}$

$\boxed{\begin{array}{l}\rm 2)\\\tt a)~\sf\dfrac{5}{7}=\dfrac{x}{35}\\\sf 7x=5\cdot35\\\sf 7x=175\\\sf x=\dfrac{175}{7}\\\sf x=25\\\tt b)~\sf\dfrac{6}{11}=\dfrac{24}{x}\\\sf 6x=24\cdot11\\\sf 6x=264\\\sf x=\dfrac{264}{6}\\\sf x=44\\\tt c)~\sf\dfrac{x}{4}=\dfrac{18}{24}\\\sf 24x=4\cdot18\\\sf 24x=72\\\sf x=\dfrac{72}{24}\\\sf x=3\\\tt d)~\sf\dfrac{9}{x}=\dfrac{45}{65}\\\sf 45x=585\\\sf x=\dfrac{585}{45}\\\sf x=13\end{array}}$

$\large\boxed{\begin{array}{l}\tt e)~\sf\dfrac{6}{18}=\dfrac{x}{54}\\\sf 18x=324\\\sf x=\dfrac{324}{18}\\\sf x=18\\\tt f)~\sf\dfrac{1}{2}=\dfrac{3}{x}\\\sf x=2\cdot3\\\sf x=6\\\tt g)~\sf\dfrac{6}{x}=\dfrac{9}{12}\\\sf 9x=72\\\sf x=\dfrac{72}{9}\\\sf x=8\\\tt h)~\sf\dfrac{3}{x}=\dfrac{12}{60}\\\sf 12x=180\\\sf x=\dfrac{180}{12}\\\sf x=15\end{array}}$