Question

2) Calcule pelo processo da decomposição simultânea: a) m.m.c.(2,10) = b) m.m.c.(3,18) = c) m.m.c.(5,20) = d) mmc(8, 36) e) mmc(15, 27) f) mmc(9, 15,

Answer 1

a) m.m.c.(2,10) = 10

$2,10 | 2 \\ 1,5 | 5 \\ 1,1$

$m.m.c = 2 \times5 = 10$

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b) m.m.c.(3,18) = 18

$3.18 | 2 \\ 3.9 | 3 \\ 1.3 | 3 \\ 1.1$

$m.m.c = 2 \times 3 \times 3 = 18$

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c) m.m.c.(5,20) = 20

$5.20 | 2 \\ 5.10 | 2 \\ 5.5 | 5 \\ 1.1$

$m.m.c =2 \times 2 \times 5 = 20$

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d) m.m.c(8, 36) = 72

$8.36 | 2 \\ 4.18 | 2 \\ 2.9 | 2 \\ 1 | 3 \\ 1.1$

$m.m.c = 2 \times 2 \times 2 \times 3 \times 3 = 72$

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e) m.m.c(15, 27) = 135

$15.27 | 3 \\ 5.9 | 3 \\ 5.3 | 3 \\ 5.1 | 5 \\ 1.1$

$m.m.c = 3 \times 3 \times 3 \times 5 = 135$

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f) m.m.c(9, 15) = 45

$9.15 | 3 \\ 3.5 | 3 \\ 1.5 | 5 \\ 1.1$

$m.m.c = 3 \times 3 \times 5 = 45$

Answer 2

Explicação passo-a-passo:

a) 2, 10 : 2

1, 5 : 5

1, 1 então 2x5=10 m.m.c (2, 10) = 10

b) 3, 18 : 2

3, 9 :! 3

1, 3 : 3

1 1 , então 2x3²= 2x9 =18

c) 5, 20 : 2

5, 10 :2

5 5 : 5

1, 1 m.m.c (5, 20)=2²x5=4x5=20

d) 8, 36 : 2

4, 18 : 2

2, 9 : 2

1, 9 : 3

1, 3 : 3

1, 1 então m.m.c (8, 36)=2³x3²=8x9=72

e)15 27 : 3

5 9 : 3

5, 3 : 3

5, 1 : 5

1, 1

1, 1 então m.m.c (15, 27)=135 3³x5=27x5=135

f) 9, 15 : 3

3, 5 : 3

1, 5 : 5

1, 1 então m.m.c (9, 15) =3²x5= 9x5=45