Question

2) Calcule os seguinte logaritmos​

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{a)\:log_2\:32 = x \iff 2^x = 32 \iff \not2^x = \not2^5 \iff x = 5}$

$\mathsf{b)\:log_3\:81 = x \iff 3^x = 81 \iff \not3^x = \not3^4 \iff x = 4}$

$\mathsf{c)\:log_{25}\:125 = x \iff 25^x = 125 \iff \not5^{2x} = \not5^3 \iff x = \dfrac{3}{2}}$

$\mathsf{d)\:log_7\:49 = x \iff 7^x = 49 \iff \not7^x = \not7^2 \iff x = 2}$

$\mathsf{e)\:log_7\:343 = x \iff 7^x = 343 \iff \not7^x = \not7^3 \iff x = 3}$

$\mathsf{f)\:log_5\:625 = x \iff 5^x = 625 \iff \not5^x = \not5^4 \iff x = 4}$

Answer 2

Explicação passo-a-passo:

Resposta:

\textsf{Leia abaixo}Leia abaixo

Explicação passo a passo:

\mathsf{a)\:log_2\:32 = x \iff 2^x = 32 \iff \not2^x = \not2^5 \iff x = 5}a)log

2

32=x⟺2

x

=32⟺



2

x

=



2

5

⟺x=5

\mathsf{b)\:log_3\:81 = x \iff 3^x = 81 \iff \not3^x = \not3^4 \iff x = 4}b)log

3

81=x⟺3

x

=81⟺



3

x

=



3

4

⟺x=4

\mathsf{c)\:log_{25}\:125 = x \iff 25^x = 125 \iff \not5^{2x} = \not5^3 \iff x = \dfrac{3}{2}}c)log

25

125=x⟺25

x

=125⟺



5

2x

=



5

3

⟺x=

2

3

\mathsf{d)\:log_7\:49 = x \iff 7^x = 49 \iff \not7^x = \not7^2 \iff x = 2}d)log

7

49=x⟺7

x

=49⟺



7

x

=



7

2

⟺x=2

\mathsf{e)\:log_7\:343 = x \iff 7^x = 343 \iff \not7^x = \not7^3 \iff x = 3}e)log

7

343=x⟺7

x

=343⟺



7

x

=



7

3

⟺x=3

\mathsf{f)\:log_5\:625 = x \iff 5^x = 625 \iff \not5^x = \not5^4 \iff x = 4}f)log

5

625=x⟺5

x

=625⟺



5

x

=



5

4

⟺x=4