Question

2 calcule o valor de log​

Answer 1

Resposta:

2/3 e 64

Explicação passo-a-passo:

$Log_{2^3} \sqrt[3]{2^6} =\frac{1}3{}Log_{2} 2^\frac{6}{3}} =\frac{1}3{}Log_{2} 2^2} =\frac{2}{3}Log_{2} 2}=\boxed{\frac{2}{3}}\\\\\27^{Log_{3} 4}=(3^3)^{Log_{3} 4}=3^{Log_{3} 4^3}=3^{Log_{3} 64}=64$