Question

2) Calcule o valor das expressões (expoente positivo):


a) 5² : ( 5 +1 -1)+ 4 x 2 =


b) (3 +1)² +2 x 5 - 10⁰ =

c) c) 3²: ( 4 – 1) + 3 x 2² =


d) 5² + 2³ - 2 x (3 + 9) =

e) 6² : 3² + 4 x 10 – 12 =


f) (7² - 1 ) : 3 + 2 x 5 =


g)5³ x 2² - 12 =


h)( 5 + 1 )² + 10 =


i) ( 9 – 7 )³ x 8 =


j) ( 7² - 5²) + ( 5² - 3 ) =


k) 6² : 2 - 1⁴ x 5 =

l) 3² x 2³ + 2² x 5² =


m) 4²- 10 + (2³ - 5) =


n) 30 – (2 + 1)²+ 2³ =


o)2³ x 5 + 3² =


p)3 x 7¹ - 4 x 5⁰ =

q)5² - 3 x 2² - 1 =


r)70 –[5 x (2² : 4) + 3²] =


s) ( 7 + 4) x ( 3² - 2³) =

Answer 1

Resposta:

a)5²:(5+1-1)+4×2=

25:5+4×2

=5+4×2

=5+8

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