2. Calcule o m.m.c utilizando o 2º método (decomposição em fatores primos)
a) m.m.c (8,10)
b) m.m.c (12, 20)
c) m.m.c (7, 5)
d) m.m.c (8, 9)
e) m.m.c (60, 24)
f) m.m.c (18, 30)
g) m.m.c (3, 6, 9)
h) m.m.c (10, 12, 45)
i) m.m.c (6, 8, 12, 15)
j) m.m.c (12, 18, 36, 40)
Soluções para a tarefa
Resposta e explicação passo-a-passo:
a) m.m.c (8,10)
8, 10 | 2
4, 5 | 2
2, 5 | 2
1, 5 | 5
1, 1
2 x 2 x 2 x 5 = 40
b) m.m.c (12, 20)
12, 20 | 2
6, 10 | 2
3, 5 | 3
1, 5 | 5
1, 1
2 x 2 x 3 x 5 = 60
c) m.m.c (7, 5)
7, 5 | 5
7, 1 | 7
5 x 7 = 35
d) m.m.c (8, 9)
8, 9 | 2
4, 9 | 2
2, 9 | 2
1, 9 | 3
1, 3 | 3
1, 1
2 x 2 x 2 x 3 x 3 = 8 x 9 = 72
e) m.m.c (60, 24)
60, 24 | 2
30, 12 | 2
15, 6 | 2
15, 3 | 3
5, 3 | 3
5, 1 | 5
1, 1
2 x 2 x 2 x 3 x 3 x 5 = 8 x 9 x 5 = 72 x 5 = 360
f) m.m.c (18, 30)
18, 30 | 2
9, 15 | 3
3, 5 | 3
1, 5 | 5
1, 1
2 x 3 x 3 x 5 = 18 x 5 = 90
g) m.m.c (3, 6, 9)
3, 6, 9 | 2
3, 3, 9 | 3
1, 1, 3 | 3
1, 1, 1
2 x 3 x 3 = 18
h) m.m.c (10, 12, 45)
10, 12, 45 | 2
5, 6, 45 | 2
5, 3, 45 | 3
5, 1, 15 | 3
5, 1, 5 | 5
1, 1, 1
2 x 2 x 3 x 3 x 5 = 180
i) m.m.c (6, 8, 12, 15)
6, 8, 12, 15 | 2
3, 4, 6, 15 | 2
3, 2, 3, 15 | 2
3, 1, 3, 15 | 3
1, 1, 1, 5 | 5
1, 1, 1, 1
2 x 2 x 2 x 3 x 5 = 120
j) m.m.c (12, 18, 36, 40)
12, 18, 36, 40 | 2
6, 9, 18, 20 | 2
3, 9, 9, 10 | 2
3, 9, 9, 5 | 3
1, 3, 3, 5 | 3
1, 1, 1, 5 | 5
1, 1, 1, 1
2 x 2 x 2 x 3 x 3 x 5 = 360
Bons estudos.