Question

2- Calcule e (P-1) (P-2) para a P-5​

Answer 1

Resposta:

Como resolver esse problema

Veja o problema a seguir:

(

−

1

)

(

−

2

)

⋅

−

5

e(p-1)(p-2) \cdot pap-5

e(p−1)(p−2)⋅pap−5

Simplifique

1

Aplique a propriedade distributiva

(

−

1

)

(

−

2

)

⋅

−

5

{\color{#c92786}{e(p-1)(p-2) \cdot pap}}-5

e(p−1)(p−2)⋅pap−5

(

−

2

)

⋅

3

−

(

−

2

)

⋅

2

−

5

{\color{#c92786}{ae(p-2) \cdot p^{3}-ae(p-2) \cdot p^{2}}}-5

ae(p−2)⋅p3−ae(p−2)⋅p2−5

Solução

4

−

3

3

+

2

2

−

5

(

−

1

)

(

−

2

)

⋅

−

5