Question

2 Calcule a medida x nas figuras a seguir. ​

Answer 1

Efetuados os cálculos, obteve-se os seguintes valores para o ângulo x.

$a) 20^0\\b) 40^0$

a) Nesta figura temos um ângulo igual a $90^0$.

$x + 15^0 + 3x - 5^0 = 90^0\\\\4x = 90^0 - 15^0 + 5^0\\\\4x = 80^0\\\\x = 80^0 / 4\\\\x = 20^0$

b) Nesta figura temos um ângulo igual a $180^0$

$3x + 20^0 + x = 180^0\\\\4x = 180^0 - 20^0\\\\4x = 160^0\\\\x = 160^0 / 4\\\\x = 40^0$

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Answer 2

$\Large\boxed{\begin{array}{l}\sf a)~x+15^\circ+3x-5^\circ=90^\circ\\\sf 4x+10=90^\circ\\\sf 4x=90^\circ-10^\circ\\\sf 4x=80^\circ\\\sf x=\dfrac{80^\circ}{4}\\\\\sf x=20^\circ\end{array}}$

$\Large\boxed{\begin{array}{l}\sf b)~x+3x+20^\circ=180^\circ\\\sf 4x+20^\circ=180^\circ\\\sf 4x=180^\circ-20^\circ\\\sf 4x=160^\circ\\\sf x=\dfrac{160^\circ}{4}\\\\\sf x=40^\circ\end{array}}$