Física, perguntado por soareskah333, 10 meses atrás

2) Calcule:
a) 6!
b)5!-4!
c)12!3!/15!
d)4*2!​

Soluções para a tarefa

Respondido por marleysantos439
2

Explicação:

A)

6! = 6 \times (6 - 1) \times (6 - 2) \times (6 - 3) \times (6 - 4) \times (6 - 5) \times (6 - 6)! = \\  6 \times 5 \times 4 \times 3 \times 2 \times 1 \times 0! = 720

B)

5!  - 4!  \\  5 \times (5 - 1) \times (5 - 2) \times (5 - 3) \times (5 - 4) \times (5 -5)! = 5 \times 4 \times 3 \times 2 \times 1 \times 0! = 120 \\ 4! = 4 \times (4 - 1) \times (4 - 2) \times (4 - 3) \times (4 - 4)! = 4 \times 3 \times 2 \times 1 \times 0! = 24 \\ 5! - 4! = 120 - 24 = 96

 \frac{12! \times 3!}{15!}  =  \frac{12! \times 3!}{3! \times 5!}  =  \frac{3!}{3!}  \times  \frac{12!}{5!}  = 1 \times  \frac{12 \times 11 \times 10 \times9 \times 8 \times 7 \times 6 \times 5! }{5!}  =  \frac{5!}{5!}  \times  12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 =  \\ 1 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 = 3.991.680

D)

4 \times 2! = 4 \times 2 = 8

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