Question

2^98+4^50-8^14/2^99-32^20+2^101 como efetuar​

Answer 1

Resposta:

Explicação passo-a-passo:

Obs.:

- 8^14 fica assim.

(2^98+4^50-8^14)

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(2^99-32^20+2^101 )

Numerador:

(2)^98 + (2^2)^50 - (2^3)^14

2^98 + 2^100 - 2^42

2^42.(2^56 + 2^58 - 1)

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Parte do denominador

(2^99-32^20+2^101 )

(2)^99 - (2^5)^20 + 2^101

2^99 - 2^100 + 2^101

2^99 .(1 - 2 + 2^2)

2^99.(-1 + 4)

2^99 . (-3)

2^42.(2^56 + 2^58 - 1)

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2^99 . (-3)

=

2^(-99).2^42.(2^56 +2^58 - 1)

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(-3)

=

[2^(-57).(2^56 + 2^58 - 1) ]/ (-3)

[2^(-1)+2^1 - 2^57]/(-3)

[1/2 + 2 - 2^57]/(-3)

[1/2+4/2 - 2^57]/(-3)

(5/2 - 2^57)/(-3)

(- 5/2 + 2^57)/3