Question

{2^8 - [3^4 - √169 - (2^5 + 4^0) x 2^2) - 1] + 10^0}

Answer 1

{2^8-[3^4-V169-(2^5+4^0)x2^2)-1]+10^0}=
{256-[81-13-(32+1)x4-1]+1}=
{256-[81-13-33x4-1]+1}=
{256-[81-13-132-1]+1}=
{256-[68-132-1]+1}=
{256-[-64-1]+1}=
{256-[-65]+1}=
{256+65+1}=
{321+1}=
322