Question

[2^7 . (2^7 : (2^3 . 2)^2]^-2= ?

Algebra~

Answer 1

$\boxed{\left[\frac{2^7.2^7}{2^3.2}\right]^{-2}=\left[\frac{2^{14}}{2^4}\right]^{-2}=\left[2^{10}\right]^{-2}=2^{-20}=\frac{1}{2^{20}}}$