Question

-^2+6x-5=0 preciso da delta e bhaskara

Answer 1

x^2+6x-5=0
delta=b^2-4ac
delta=(+6)^2-4.1.(-5)
delta=36+20
delta=56

x=-b+-raiz delta /2a
x=-6+-raiz 56/2a
x=-6+-2raiz14/2.1
x=-6+2raiz14/2
x=-6+2raiz14/2
x=-3+2raiz14

x=-6-2raiz14/2
x=-3-2raiz14