2/5∧x+3 = 4∧125/8∧x-1 . (0,4) ∧2x-3 - equação exponencial
Barbaramills:
2/5 (base) X+3(expoente) = 125 (base) x-1 expoente vezes 4/10 (base) 2x-3 espoente
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Oi Barbara
(2/5)^(x + 3) = (125/8)^(x - 1)*(4/10)^(2x - 3)
(2/5)^(x + 3) = (5/2)^(3x - 3)*(2/5)^(2x - 3)
(2/5)^(x + 3) = (2/5)^(3 - 3x)*(2/5)^(2x - 3)
(2/5)^(x + 3) = (2/5)^(3 - 3x + 2x - 3)
(2/5)^(x + 3) = (2/5)^(-x)
x + 3 = -x
2x = -3
x = -3/2
(2/5)^(x + 3) = (125/8)^(x - 1)*(4/10)^(2x - 3)
(2/5)^(x + 3) = (5/2)^(3x - 3)*(2/5)^(2x - 3)
(2/5)^(x + 3) = (2/5)^(3 - 3x)*(2/5)^(2x - 3)
(2/5)^(x + 3) = (2/5)^(3 - 3x + 2x - 3)
(2/5)^(x + 3) = (2/5)^(-x)
x + 3 = -x
2x = -3
x = -3/2
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