Question

2.4 Resolva as expressões numéricas:
a) 230 + 72 : 6 =
b) (50 - 35): 3 + 6 x 5 =
c) (17 - 5) x (17 + 5) – 15 =
​

Answer 1

$\large\boxed{\begin{array}{l}\underline{\rm Em\,uma\,express\tilde ao\,num\acute erica\,resolve-se:}\\\sf 1^a~Pot\hat encias\,e\,ra\acute izes\,na\,ordem\,que\,vier\\\sf 2^a\,Multiplicac_{\!\!,}\tilde ao\,e\,divis\tilde ao\,na\,ordem\,que\,vier\\\sf 3^a\,adic_{\!\!,}\tilde ao\,e\,subtrac_{\!\!,}\tilde ao\,na\,ordem\,que\,vier.\\\underline{\rm Al\acute em\,disso\, eliminamos:}\\\sf 1^a~\bigg(\bigg)\\\\\sf 2^a\bigg[~~\bigg]\\\\\sf 3^a\bigg\{~\bigg\}\end{array}}$

$\large\boxed{\begin{array}{l}\rm a)~\sf230+72\div6\\\sf aqui,vamos\,resolver\,a\,divis\tilde ao\,primeiro:\\\sf 72\div6=12\\\sf substituindo\,temos:\\\sf 230+12=242\checkmark\end{array}}$

$\large\boxed{\begin{array}{l}\rm b )~\sf(50-35)\div3+6\times5\\\sf resolvendo\,os\,par\hat enteses\,temos:\\\sf 50-35=15.\\\sf dessa\,forma\,teremos:\\\sf 15\div3+6\times 5\\\sf resolve\,divis\tilde ao\,agora:\\\sf 15\div3=5\\\sf substituindo\,temos:\\\sf 5+6\times5\\\sf resolvendo\,multiplicac_{\!\!,}\tilde ao\,temos: \\\sf 6\times5=30\\\sf substuindo:\\\sf 5+30=35\checkmark\end{array}}$

$\large\boxed{\begin{array}{l}\rm c)~\sf (17-5)\times(17+5)-15\\\sf resolvendo\,os\,par\hat enteses\,temos:\\\sf 17-5=12~~~~~~17+5=22\\\sf substuindo:\\\sf 12\times22-15\\\sf12\times22=264\\\sf 264-15=249\end{array}}$