Question

×_2 4× + 3=0
como resolver essa equação do 2 - grau?

Answer 1

x²+4x+3=0
a=1;b=4;c=3
Δ=b²-4ac
Δ=4²-4.1.3
Δ=16-12
Δ=4

x=$\frac{-b+-√Δ}{2a}$
x=$\frac{-4+-√4}{2.1}$
x=$\frac{-4+-2}{2}$
x=$\frac{-4+2}{2}$=$\frac{-2}{2}$=-1
e $\frac{-4-2}{2}$=$\frac{-6}{2}$=-3

∴V={-1;-3}