Question

2
3y+2=0
2
3y-7y+2=0

Answer 1

A) 3y + 2 = 0
3y = 0 + 2
3y = 2
y = 2/3
y = $\frac{2}{3}$

B) 3y - 7y + 2 = 0
-4y = 0 - 2
-4y = -2
(-1). -4y = -2 .(-1)
4y = 2 
y = 2/4
y = 0,5 ou $\frac{1}{2}$