Matemática, perguntado por annakarolinamarrocos, 1 ano atrás

(2/3)^x-1 *(4/9)^3x/2 * (27/8)^-x+1

Soluções para a tarefa

Respondido por 3478elc
2

   

(2/3)^x-1 *(4/9)^3x/2 * (27/8)^-x+1
(2/3)^x-1*[(2/3)^2]^3x/2 *[(3/2)^3]^-x+12/3)^x-1*(2/3)^6x/2 *[(3/2)^-3]^-x+12/3)^x-1*(2/3)^3x *(2/3)^3x+3(2/3)^7x + 2

Perguntas interessantes