Question

[2⁄3 + 3 • (-2⁄9) ] ajudemmm PF

Answer 1

$\boxed{\boxed{Ola\´ \: \: Junior} }$

$\frac{2}{3} + 3 \cdot \big( - \frac{2}{9} \big) \\ = \frac{2}{3} + \cancel{3} \cdot \big( - \frac{2}{3 \cdot \cancel{3} } \big) \\ = \frac{2}{3} - \frac{2}{3} \\ = \cancel{\frac{2}{3}} - \cancel{\frac{2}{3}}$
$= \boxed{\boxed{0} }} \end{array}\qquad\checkmark$

$\textbf{Bons estudos}$ !

Answer 2

let,s Go !


$( \frac{2}{3} +3 .( - \frac{2}{9}) )= > ( \frac{2}{3} +( - \frac{6}{9}) = > \frac{2}{3} + ( - \frac{6 \div 3}{9 \div 3} ) = > \frac{2}{3} - \frac{2}{3} = > \frac{2 - 2}{3 - 3} = > \frac{0}{0} = > 0$

espero ter ajudado!


boa tarde!


bye!