Question

(-⅖)÷[2^-3(-2+4/5)+6/10]=

Answer 1

$(- \frac{2}{5} ):[2^-^3(-2+ \frac{4}{5} )+ \frac{6}{10}]=$

$(- \frac{2}{5} ):[2^-^3(-\frac{6}{5} )+ \frac{6}{10}]=$

$(- \frac{2}{5} ):[ \frac{1}{2^3} (-\frac{6}{5} )+ \frac{6}{10}]=$

$(- \frac{2}{5} ):[ \frac{1}{8} (-\frac{6}{5} )+ \frac{6}{10}]=$

$(- \frac{2}{5} ):[-\frac{6}{40}+ \frac{6}{10}]=$

$(- \frac{2}{5} ):[-\frac{3}{20}+ \frac{3}{5}]=$

$- \frac{2}{5} :\frac{9}{20}=- \frac{2}{5}.\frac{20}{9}=- \frac{2}{1}.\frac{4}{9}=\boxed{ \frac{8}{9}}$