Question

(2+2i) elevado a -2 ?​

Answer 1

$(2 + 2i) {}^{ - 2} \\ \\ \frac{1}{(2 + 2i) {}^{2} } = \frac{1}{2 {}^{2} + 2 \times 2 \times 2i + (2i) {}^{2} } \\ \\ \frac{1}{4 + 8i + 4i {}^{2} } = \frac{1}{4 + 8i + 4( - 1)} \\ \\ \frac{1}{4 + 8i - 4} = \frac{1}{8i} = 8i {}^{ - 1}$