Matemática, perguntado por victorgames9093, 8 meses atrás

2) 2(2x + 7 ) + 3(3x – 5 ) = 3(4x – 5 ) – 1

3) 3( x + 2 ) = 2 ( x – 7)

4) 4(2x –1 ) = 3( x+2 )

5) 4(2m-1) + 3m = 2(4m-1) – (2 –m)

6) 3(x + 3 ) - 1 = 2

7) 3(x + 2 ) – 1 = 2(x + 3) – 7

8) 3(x + 1 ) + 2 = 5 + 2(x - 1 )

9) 3(2x – 3 ) + x = 5

10)3x + 5 + 2x + 6= x + 27

11) 2 ( x – 1 ) + 3(x + 1 ) = 4(x + 2)

12) 3(x + 1) + 2(2x – 3) = 5 (x – 1 ) + 8

Soluções para a tarefa

Respondido por weslleyreis103
3

Resposta:

3) 3x +6=2x-14

3x-2x= -6-14

1x= -20

×=-20÷1

×= -21

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