Question

2+∨2
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∨2-1

Answer 1

$\dfrac{2. \sqrt{2}}{ \sqrt{2} - 1 } \\ \\ \\ \dfrac{(2. \sqrt{2}) . (\sqrt{2} - 1)}{( \sqrt{2} - 1 ) . ( \sqrt{2} - 1)} \\ \\ \\ \dfrac{4 -2\sqrt{2}}{3 - 2\sqrt{2}} \\ \\ \\ (4 - 2 \sqrt{2}) . (3 + 2 \sqrt{2}) \\ \\ \\ =\ \textgreater \ 4 + \sqrt{2}$