Question

2(1+x) sobre 3 - 3(x+1) sobre 4 = 1 sobre 6 determine o valor de x

Answer 1

$\frac{2(1+x)}{3} - \frac{3(x+[tex] \frac{8(1+x)-9(x+1)}{12} = \frac{2}{12}$1)}{4} = \frac{1}{6} [/tex]

$8x - 9x + 8 - 9 - 2 = 0$

$x = - 3$