Matemática, perguntado por marylauarinha, 5 meses atrás

1983-1954 e pra uma prova relp

Soluções para a tarefa

Respondido por Usuário anônimo
1

\begin{matrix}\space\space&1&9&8&3\\ -&1&9&5&4\end{matrix}

\begin{matrix}\space\space&\space\space&\space\space&\textbf{7}&10\\ \space\space&1&9&\textbf{\linethrough{8}}&3\\ -&1&9&\textbf{5}&4\end{matrix}

\begin{matrix}\space\space&\space\space&\space\space&7&\textbf{13}\\ \space\space&1&9&\linethrough{8}&\textbf{\linethrough{3}}\\ -&1&9&5&\textbf{4}\end{matrix}

\frac{\begin{matrix}\space\space&\space\space&\space\space&7&\textbf{13}\\ \space\space&1&9&\linethrough{8}&\textbf{\linethrough{3}}\\ -&1&9&5&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\space\space&\textbf{9}\end{matrix}}    9

           

\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{7}&13\\ \space\space&1&9&\textbf{\linethrough{8}}&\linethrough{3}\\ -&1&9&\textbf{5}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{2}&9\end{matrix}}  29

               

\frac{\begin{matrix}\space\space&\space\space&\textbf{\space\space}&7&13\\ \space\space&1&\textbf{9}&\linethrough{8}&\linethrough{3}\\ -&1&\textbf{9}&5&4\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{0}&2&9\end{matrix}} 029

\frac{\begin{matrix}\space\space&\textbf{\space\space}&\space\space&7&13\\ \space\space&\textbf{1}&9&\linethrough{8}&\linethrough{3}\\ -&\textbf{1}&9&5&4\end{matrix}}{\begin{matrix}\space\space&\textbf{0}&0&2&9\end{matrix}} 0029

= 29


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