Question

16x²-4=0 resolva a equação

Answer 1

X' (16X"-4) = 0 X'=0 e 16X"-4=0 16X"=4 X"=4/16 X"= 1/4

Answer 2

Boa Noite!

$16x^{2} -4=0 \\ 16x^{2}=4 \\ \sqrt{x^{2}} =+- \sqrt{ \frac{4}{16} } \\ x=+- \frac{2}{4}$
ou seja $x= +-\frac{1}{2}$

Teste:
$16* (\frac{1}{2} ^{2} )-4=0 \\ 16* \frac{1}{4} -4=0 \\ 4-4=0 \\ \\ 16* (- \frac{1}{2} ^{2}) -4=0 \\ 16* \frac{1}{4} -4=0 \\ 4-4=0$
$S={- \frac{1}{2}; \frac{1}{2} }$