Question

16²$16 ^{3x-1} = \frac{1}{128}$

Answer 1

EXPONENCIAL

Equação Exponencial

$16 ^{3x-1}= \frac{1}{128}$

$(2 ^{4}) ^{3x-1}=2 ^{-7}$

$2 ^{12x-4} =2 ^{-7}$

Se eliminarmos as bases, podemos trabalhar com os expoentes:

$12x-4=-7$

$12x=-3$

$x=- \frac{1}{4}$