Question

(16^x)x+1=1/2 por favor eu gostaria de ter o cálculo junto obg

Answer 1

$(16^{x})^{x+1}$ = 1/2
$16^{x^{2}+ x }$ = 1/2
$(2^{4})^{x^{2} + x}$ = 2⁻¹
$2^{4x^{2} +4x}$ = 2⁻¹

4x² + 4x = -1
4x² + 4x + 1 = 0

Δ= 16-4.4.1
Δ=16-16
Δ=0

x = -4/4
x = -1