Question

-15$x^{2}$-5x=0

Answer 1

$-15 x^{2} -5 x^{} =0$

$-5x(3x+1)=0$

$-5 x^{} =0$

x=0

$3 x^{} +1=0$

$x^{} = \frac{-1}{3}$


S={0,$\frac{-1}{3} }$}