Question

15. Seja h : R → R, sendo h(x) = x2 + 4x − 8. Calcule:
(a) h(2)
(b) h(−5)
(c) h(−1)
(d) h(4)​

Answer 1

Resposta:

a) h(2) = (2).2 + 4.(2) - 8

= 4 + 8 - 8

= 4

b) h(-5) = (-5).2 + 4.(-5) - 8

= -10 + (-20) - 8

= - 38

c) h(-1) = (-1).2 + 4.(-1) - 8

= -2 + (-4) - 8

= - 14

d) h(4) = (4).2 + 4.(4) - 8

= 8 + 16 - 8

= 16