Question

14x²-29x+12=0? resposta pfvr 

Answer 1

14x2-29x+12=0

a = 14 b = -29 c = 12

∆ = b² - 4.a.c
∆ = -29²-4.14.12
∆ = 841 - 672
∆ = 169

x = b +/- √∆ / 2.a
x = -29 +/- √169 / 2.14
x = -29 +/- 13 / 28

x' = -29 + 13 / 28
x' = -0,57

x" = -29 - 13 / 28
x" = 42 / 28
x" = 1,5

Answer 2

Olá, bom dia ☺

Resolução:

14x² - 29x + 12 =0

Coeficientes:

a=14, b=-29, c= 12

Δ=b²-4.a.c
Δ=(-29)²-4.14.12
Δ=841 - 672
Δ=169

Valores de x:

x= -b ±√Δ / 2.a
x= -(-29)±√169 / 2.14
x=29 ± 13/ 28

x'=29 + 13/28 = 42/28 : 14/14 = 3/2

x''=29 - 13/28=16/28 : 4/4 = 4/7

Bons estudos :)