Question

14 pontos pra quem me responder !

1) Seja o angulo agudo x tal que cos x = 7/25 ; determine sen.x

Answer 1

cos²x + sen²x=1

$( \frac{7}{25}) ^{2} +sen ^{2}x =1$

$\frac{49}{625} +sen ^{2} x=1$

sen²x=$1+ \frac{49}{625}$

sen²x=$\frac{576}{625}$

senx=$\sqrt{ \frac{576}{625} } =$

senx=+ ou -$\frac{24}{25}$