Question

13.Marque um "X" nos pares que representam arcos côngruos.
( )740° e 1460°
( ) 400° e 940°
( ) 38π/3 rad e 26π/3 rad.
( ) 74π/5 rad e 19π/5 rad.

Answer 1

$\boxed{\begin{array}{l}\sf 740^\circ=2\cdot360^\circ+\boxed{\sf20^\circ}\\\sf 1460^\circ=4\cdot360^\circ+\boxed{\sf 20^\circ}\\\sf 740^\circ~e~1460^\circ~s\tilde ao~c\hat ongruos\\\sf 400^\circ=1\cdot360^\circ+\boxed{\sf 40^\circ}\\\sf 940^\circ=2\cdot360^\circ+\boxed{\sf220^\circ}\\\sf 400^\circ~e~940^\circ~n\tilde ao~s\tilde ao~c\hat ongruos\end{array}}$

$\boxed{\begin{array}{l}\sf \dfrac{38\pi}{3}~rad=\dfrac{36\pi}{3}+\dfrac{2\pi}{3}=6\cdot2\pi+\boxed{\sf\dfrac{2\pi}{3}}\\\\\tt~\sf\dfrac{26\pi}{3}~rad=\dfrac{24\pi}{3}+\dfrac{2\pi}{3}=4\cdot2\pi+\boxed{\sf\dfrac{2\pi}{3}}\\\\\sf os~arcos~\dfrac{38\pi}{3}~rad~e~\dfrac{26\pi}{3}~rad~s\tilde ao~congruentes\end{array}}$

$\boxed{\begin{array}{l}\sf\dfrac{74\pi}{5}~rad=\dfrac{70\pi}{5}+\dfrac{4\pi}{5}=7\cdot2\pi+\boxed{\sf\dfrac{4\pi}{5}}\\\\\sf \dfrac{19\pi}{5}=\dfrac{10\pi}{5}+\dfrac{9\pi}{5}=2\pi+\boxed{\sf\dfrac{9\pi}{5}}\\\\\sf os~arcos~\dfrac{74\pi}{5}~e~\dfrac{19\pi}{5}~n\tilde ao~s\tilde ao~c\hat ongruos\end{array}}$