Question

12x²-mx-1=0 de modo que a soma das raízes seja 5/3

Answer 1

x+x'=-b/a

5/3=-(-m)/12

5/3=m/12

3m=5.12

3m=60

m=60/3

m=20

12x²-20x-1=0

Resposta: m=20

Answer 2

12x² -mx -1 =0

a=12

b=-m

$Soma={-b\over a}\\ \\ {-(-m)\over12}={5\over3}\\ \\ {m\over12}={5\over3}\\ \\ 3m=5.(12)\\ \\ 3m=60\\ \\ m=60\div3\\ \\\\m=20$