Question

12 – Determine:
a. log² 128
b. log√3⁹

Answer 1

Resposta:

Explicação passo-a-passo:

a) log²128 = log128 . log128 = log2⁷ . log2⁷ = 7.log2 . 7 log2 = 49.log²2 =                49.(0,3010)² = 49 .  0,3010 = 4,4394

b) log√3⁹ = 9 log√3 = 9 . log 3¹/² = 9.1/2 log3 = 4,5.0,4771 = 2,14695