Question

11)Calcule.

√6 + √1 - √1
          9     4

Answer 1

$\boxed{ \sqrt{6}+ \sqrt{ \frac{1}{9} }- \sqrt{ \frac{1}{4} }~\to~ \sqrt{6} + \frac{1}{3}- \frac{1}{2}~\to~ \sqrt{6} - \frac{1}{6} }$

Answer 2

$\sqrt{6} + \sqrt{ \dfrac{1}{9} } - \sqrt{ \dfrac{1}{4} } = \sqrt{6} + \dfrac{1}{ \sqrt{9} } - \dfrac{1}{ \sqrt{4} } = \sqrt{6} + \dfrac{1}{ 3 } - \dfrac{1}{ 2 } = \dfrac{6 \sqrt{6} +2-3}{6}$$= \dfrac{6 \sqrt{6} -1}{6}$