Question

10y-5(1+y)=3(2y-2)-20 como monta ?

Answer 1

10y-5(1+y)=3(2y-2)-20
10y-5-5y=6y-6-20
10y-5y-6y=-6-20+5
10y-11y=-26+5
-y=-21.(-1)
y=21

Answer 2

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}10y-5*(1+y) = 3*(2y-2)-20\\\\10y-5-5y = 6y-6-20\\\\10y-5y-6y = -6-20+5\\\\-y =-21\\\\\boxed{\boxed{y = 21}} \end{array}\right$

Espero ter ajudado. =^.^=