Question

10y-5(1+y)=3(2y-2)-20

Answer 1

10y-5-5y=6y-12-20
10y-5y-6y=6-32
-y=-26
y=26

Answer 2

10y-(5*1+5*y)=3*(2y-2)-20
10y-(5+5*y)=3*(2y-2)-20
10y-(5+5y)=3*(2y-2)-20
10y-5-5y=3*(2y-2)-20
5y-5=3*2y-3*2-20
5y-5=6y-6-20
5y-5=6y-26
5y-6y=-26+5
-y=-26+5
-y=-21
y=21