Question

10y-5(1+y)=3(2y-2)-20

Answer 1

10y-5(1+y) = 3(2y-2)20
10y -5 -5y = 6y -6 +20
5y -5 = 6y 14
5y -6y = 14 +5
-y =19 (multiplica tido por -1)
y = 19

Answer 2

eu sei 

10-5(1+y)=3(2y-2)-20
10-5-5y=6y+1-20
5y-6y=1-20-10+5
1y= -19-15
1y= -34
y=-34:1
y=-34