Question

10y-5(1+y)= 3(2y-2) - 20

Answer 1

10y-5(1+y)=3(2y-2)-20
10y-5-5y=6y-6-20
5y-5=6y-26
5y-6y=-26+5
-y=-21
y=21

Answer 2

10y-5(1+y) =  3(2y-2)-20
10y-5-5y = 6y-6-20
-y = -21(-1)
y = 21