10x2-7x+1=0 (formula em delta)
Soluções para a tarefa
Respondido por
32
10x²-7x+1=0
a=10
b=-7
c=1
∆=b²-4ac
∆=(-7)²-4.10.1
∆=49-40
∆=9
√∆=3
-b±√∆/2a
7±3/20
x'=7+3/20
x'=10/20
x'=1/2
X"=7-3/20
x"= 4/20
x"=1/5
a=10
b=-7
c=1
∆=b²-4ac
∆=(-7)²-4.10.1
∆=49-40
∆=9
√∆=3
-b±√∆/2a
7±3/20
x'=7+3/20
x'=10/20
x'=1/2
X"=7-3/20
x"= 4/20
x"=1/5
Perguntas interessantes