10x²=1+3x ajunda porfavor ?
Soluções para a tarefa
Respondido por
5
10 x²-3x-1=0
delta=b²-4ac
delta=3²-4.10.-1
delta=49
x=-b+/- raiz² delta/2a
x=3+-7/20
x¹=3+7/20=10/20=1/2
x²=3-7/20=-4/20=-1/5
delta=b²-4ac
delta=3²-4.10.-1
delta=49
x=-b+/- raiz² delta/2a
x=3+-7/20
x¹=3+7/20=10/20=1/2
x²=3-7/20=-4/20=-1/5
Respondido por
7
10x² = 1 + 3x
10x² - 3x - 1 = 0
a = 10; b = - 3; c = - 1
Δ = b² - 4ac
Δ = (-3)² - 4.10.(-1)
Δ = 9 - 40.(-1)
Δ = 9 + 40
Δ = 49
a = 10; b = - 3; c = - 1
x = - b +/- √Δ - (-3) +/- √49
-------------- = ------------------
2a 2.10
x = 3 + 7 10 1
--------- = -------- = --------
20 20 2
x = 3 - 7 - 4 (:4) - 1
------- = -------- = --------
20 20 (:4) 5
10x² - 3x - 1 = 0
a = 10; b = - 3; c = - 1
Δ = b² - 4ac
Δ = (-3)² - 4.10.(-1)
Δ = 9 - 40.(-1)
Δ = 9 + 40
Δ = 49
a = 10; b = - 3; c = - 1
x = - b +/- √Δ - (-3) +/- √49
-------------- = ------------------
2a 2.10
x = 3 + 7 10 1
--------- = -------- = --------
20 20 2
x = 3 - 7 - 4 (:4) - 1
------- = -------- = --------
20 20 (:4) 5
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