Question

10x ao quadrado + 7x + 1 = 0​

Answer 1

Resposta:

$x^{I} =-\frac{1}{5}\\x^{II} =-\frac{1}{2}$

Explicação passo a passo:

$10^{2} +7x+1=0\\Δ=b^{2}-4ac\\Δ=7^{2}-4*10*1\\Δ=49-40=9\\Δ=9 \\\\x=\frac{-b+/-\sqrt{Δ} }{2a} \\\\x^{I}=\frac{-7+3}{20} =-\frac{4}{20} =-\frac{1}{5} \\\\x^{II}=\frac{-7-3}{20}=-\frac{10}{20}=-\frac{1}{2}$