Question

10d - 25 = 47 raiz dessa equação com cálculo
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Answer 1

$\large\boxed{\begin{array}{l}\sf Deve-se\,isolar\,os\,elementos\\\sf desconhecidos\,em\,um\,dos\,lados\,do\,sinal\,de\\\sf igual\,e\,os\,valores \,constantes\,do\,outro\,lado.\end{array}}$

$\large\boxed{\begin{array}{l}\sf Quando\, um \,termo \,da \,equac_{\!\!,}\tilde{a}o\, mudar \,de \\\sf lado \,do \,sinal \,de\, igual, devemos \,inverter\, a \\\sf operac_{\!\!,}\tilde{a}o.\, Assim, se \,tiver \,multiplicando, \\\sf passar\acute{a}\, dividindo, se\, tiver \,somando, \\\sf passar\acute{a} \,subtraindo\, e\, vice-versa.\end{array}}$

$\large\boxed{\begin{array}{l}\underline{\bf Soluc_{\!\!,}\tilde ao}\\\sf10d-25=47\\\sf10d=47+25\\\sf10d=72\\\sf d=\dfrac{72}{10}\\\sf Simplificando\,por\,2:\\\sf d=\dfrac{72\div2}{10\div2}\\\huge\boxed{\boxed{\boxed{\boxed{\sf d=\dfrac{36}{5}}}}}\end{array}}$

Answer 2

✅ Após resolver a equação do primeiro grau, concluímos que seu conjunto solução é:

            $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf S = \bigg(\frac{36}{5}\bigg)\:\:\:}}\end{gathered} }$

 

Resolvendo equação do primeiro grau:

     $\Large\displaystyle\begin{gathered}\tt 10d - 25 = 47\end{gathered}$

                $\Large\displaystyle\begin{gathered}\tt 10d = 47 + 25\end{gathered}$

                $\Large\displaystyle\begin{gathered}\tt 10d = 72\end{gathered}$

                     $\Large\displaystyle\begin{gathered}\tt d = \frac{72}{10}\end{gathered}$

                     $\Large\displaystyle\begin{gathered}\tt d = \frac{36}{5}\end{gathered}$

✅ Portanto, o conjunto solução da referida equação é:

                    $\Large\displaystyle\begin{gathered}\tt S = \bigg(\frac{36}{5}\bigg)\end{gathered}$

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