Question

103) dê o valor de: a) 7,5-4,5/2-0,5 b) -3*(-1+2)/9-10 c) 12-2*(-6)/3*(-8) d) raiz quadrada de 9-(-2)+1/(-2)elevado a 2+(-3)

Answer 1

$a) \\ \frac{7,5-4,5}{2-0,5} = \frac{3,0}{1,5} =2 \\ \\ b) \\ \frac{-3.(-1+2)}{9-10} = \frac{-3.(+)}{-1} = \frac{-3}{-1} =+3 \\ \\ c) \\ \frac{12-2.(-6)}{3.(-8)} = \frac{12+12}{-24} = \frac{+24}{-24} =-1 \\ \\ d) \\ \frac{ \sqrt{9}-(-2)+1 }{(-2)^2+(-3)} = \frac{3+2+1}{+4-3} = \frac{6}{1} =6$

Answer 2

a) 7,5-4,5/2-0,5 =
3/1,5 =
2

b) -3(-1+2)/9-10 =
3 - 6/-1 =
-3/-1 =
3

c) 12-2(-6)/3(-8) =
12+12/-24 =
24/-24 =
-1

d) √9-(-2)+1/(-2)²+(-3)
3 + 2 +1/4-3
6/1
6