Question

Помогите пожалуйста с сором даю 100 балов!

1.Упростите
x²-4x/(x+3)(x-4)

2.Сократите:
а)3ab²/9a⁴b⁵c;
b)2x⁶-5³/2x⁴-5x;
c)6(x-y)²/3y-3x

3.Вычислите:
a)6y-14/5y-4y-6/5y;
b)x²+3/x²-4-2(2x+0,5)
c)2x-4y/3x-5y-3x-6y/5y-3x

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Answer 1

x²-4x/(x+3)(x-4) =

x(x-4)/(x+3)(x-4)=

x/(x+3)(x-4)

3ab²/9a⁴b⁵c=

1/3a³b³c

2x⁶-5x³/2x⁴-5x=

x³(2x³-5)/x(2x³-5)=

x²

6(x-y)²/3y-3x=

6(x-y)²/-3(x-y)=

-2(x-y)

(6y-14)/5y-(4y-6)/5y=

[(6y-14)-(4y-6)]/5y=

[6y-14-4y+6]/5y=

(2y-8)/5y=

2(y-4)/5y

(x²+3)/(x²-4)-2(2x+0,5)/(4-x²)=

-(x²+3)/(4-x²)-2(2x+0,5)/(4-x²)=

[-(x²+3)-2(2x+0,5)]/(4-x²)=

[-x²-3-4x-1)]/(4-x²)=

(-x²-4x-4)/(4-x²)=

(x²+4x+4)/(x²-4)

(2x-4y)/(3x-5y)-(3x-6y)/(5y-3x)=

-(2x-4y)/(5y-3x)-(3x-6y)/(5y-3x)=

[-(2x-4y)-(3x-6y)]/(5y-3x)=

[-2x+4y-3x+6y]/(5y-3x)=

[-5x+10y]/(5y-3x)=

5(2y-x)/(5y-3x)