Question

100^0
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1 - (1/2)^-3    uma ajuda por favor?

Answer 1

$\frac{100^0}{1 - (\frac{1}{2})^{-3} } = \frac{1}{1 - \frac{2}{1}^3 } = \frac{1}{1 - \frac{8}{1} } = \boxed{-\frac{1}{7} }$

Answer 2

$Resolu\c{c}\~ao\to \boxed{ \frac{100^0}{1- (\frac{1}{2})^{-3}} = \frac{1}{1- (2)^{3}} = \frac{1}{1-8} = - \frac{1}{7} }$

Espero ter ajudado. :))